SUBNETTING CALCULATION
Subnetting Calculation
In this project, students are required to suggest private addressing scheme used in OUM network. Explain how you calculate the subnetting using FLSM based on the number of the faculties. Each faculty is given their network address. Assign IT Center as another subnet with their own network address. From this network address, assigned as the 4th available address as the address of the OnlineLearning System Server.
Students are allowed to do the addressing by using any subnetting of any private address class, provided that the explanation and argument for the solution are stated and explained.
SUBNETTING CALCULATION
FLSM
· Dividing an IP Network with same or equal size.
· The Subnet remains within its class Boundary
· Formula 2^n>=N (Requirements)
· Binary to Decimals
Private addressing scheme used in OUM network:192.168.0.0/24
- 8 faculty = 8 subdivide
- 8subnet is selected since it should be equal or more than the requirement(8 faculty)
Step1
Number of bit borrow
2^n >= no of subnet(subdivide)2^n=>8n=3 (bit borrow from host)
Step 2
Default Subnetting Mask : 255.255.255.0Subnetting Mask: : 255.255.255.224
Ø Total = 128+64+32 = 224
Step 3
Number of Possible Hosts
2^5 = 32
32-2 =30
192.168.0.165, which is also the server's IP address, is the 4th possible address as the address of the OnlineLearning System Server. We won't begin with 192.168.0.161 because it will be assigned to the router's IP address, and we need to find the fourth accessible address. As a result, it will start at 192.168.0.162 and so on .
Number of Possible Hosts | 2^5 = 32 32-2 =30 |
192.168.0.165, which is also the server's IP address, is the 4th possible address as the address of the OnlineLearning System Server. We won't begin with 192.168.0.161 because it will be assigned to the router's IP address, and we need to find the fourth accessible address. As a result, it will start at 192.168.0.162 and so on .